Codeforces Round #FF (Div. 2)
A
DZY Loves Hash
Codeforces
800
原题
←B →
翻译中…

DZY has a hash table with $*p*$ buckets, numbered from $0$ to $*p* - 1$. He wants to insert $*n*$ numbers, in the order they are given, into the hash table. For the $*i*$-th number $*x*_{*i*}$, DZY will put it into the bucket numbered $*h*(*x*_{*i*})$, where $*h*(*x*)$ is the hash function. In this problem we will assume, that $*h*(*x*) = *x* *mod* *p*$. Operation $*a* *mod* *b*$ denotes taking a remainder after division $*a*$ by $*b*$.

翻译中…

However, each bucket can contain no more than one element. If DZY wants to insert an number into a bucket which is already filled, we say a "conflict" happens. Suppose the first conflict happens right after the $*i*$-th insertion, you should output $*i*$. If no conflict happens, just output -1.

翻译中…

Input

翻译中…

The first line contains two integers, $*p*$ and $*n*$ $(2 ≤ *p*, *n* ≤ 300)$. Then $*n*$ lines follow. The $*i*$-th of them contains an integer $*x*_{*i*}$ $(0 ≤ *x*_{*i*} ≤ 10^{9})$.

翻译中…

Output

翻译中…

Output a single integer — the answer to the problem.

翻译中…

样例

Input #1
10 5
0
21
53
41
53
Output #1
4
InputCopy OutputCopy
Input #2
5 5
0
1
2
3
4
Output #2
-1
InputCopy OutputCopy
题目信息
题号
447A
时间限制
1 s
内存限制
256 MB
标签
模拟

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。