We call a string good, if after merging all the consecutive equal characters, the resulting string is palindrome. For example, "aabba" is good, because after the merging step it will become "aba".
Given a string, you have to find two values:
- the number of good substrings of even length;
- the number of good substrings of odd length.
Input
The first line of the input contains a single string of length $*n*$ ($1 ≤ *n* ≤ 10^{5}$). Each character of the string will be either 'a' or 'b'.
Output
Print two space-separated integers: the number of good substrings of even length and the number of good substrings of odd length.
Note
In example 1, there are three good substrings ("b", "b", and "bb"). One of them has even length and two of them have odd length.
In example 2, there are six good substrings (i.e. "b", "a", "a", "b", "aa", "baab"). Two of them have even length and four of them have odd length.
In example 3, there are seven good substrings (i.e. "b", "a", "b", "b", "bb", "bab", "babb"). Two of them have even length and five of them have odd length.
Definitions
A substring $*s*[*l*, *r*]$ $(1 ≤ *l* ≤ *r* ≤ *n*)$ of string $*s* = *s*_{1}*s*_{2}... *s*_{*n*}$ is string $*s*_{*l*}*s*_{*l* + 1}... *s*_{*r*}$.
A string $*s* = *s*_{1}*s*_{2}... *s*_{*n*}$ is a palindrome if it is equal to string $*s*_{*n*}*s*_{*n* - 1}... *s*_{1}$.
样例
bb
1 2
baab
2 4
babb
2 5
babaa
2 7
题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。