Codeforces Round 266 (Div. 2)
翻译中…
You've got array $*a*[1], *a*[2], ..., *a*[*n*]$, consisting of $*n*$ integers. Count the number of ways to split all the elements of the array into three contiguous parts so that the sum of elements in each part is the same.
翻译中…
More formally, you need to find the number of such pairs of indices $*i*, *j*$ $(2 ≤ *i* ≤ *j* ≤ *n* - 1)$, that
.
翻译中…
Input
翻译中…
The first line contains integer $*n*$ $(1 ≤ *n* ≤ 5·10^{5})$, showing how many numbers are in the array. The second line contains $*n*$ integers $*a*[1]$, $*a*[2]$, ..., $*a*[*n*]$ $(|*a*[*i*]| ≤ 10^{9})$ — the elements of array $*a*$.
翻译中…
Output
翻译中…
Print a single integer — the number of ways to split the array into three parts with the same sum.
翻译中…
样例
Input #1
5
1 2 3 0 3
Output #1
2
InputCopy
OutputCopy
Input #2
4
0 1 -1 0
Output #2
1
InputCopy
OutputCopy
Input #3
2
4 1
Output #3
0
InputCopy
OutputCopy
题目信息
标签
二分
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