Andrew skipped lessons on the subject 'Algorithms and Data Structures' for the entire term. When he came to the final test, the teacher decided to give him a difficult task as a punishment.
The teacher gave Andrew an array of $*n*$ numbers $*a*_{1}$, $...$, $*a*_{*n*}$. After that he asked Andrew for each $*k*$ from 1 to $*n* - 1$ to build a $*k*$-ary heap on the array and count the number of elements for which the property of the minimum-rooted heap is violated, i.e. the value of an element is less than the value of its parent.
Andrew looked up on the Wikipedia that a $*k*$-ary heap is a rooted tree with vertices in elements of the array. If the elements of the array are indexed from 1 to $*n*$, then the children of element $*v*$ are elements with indices $*k*(*v* - 1) + 2$, $...$, $*kv* + 1$ (if some of these elements lie outside the borders of the array, the corresponding children are absent). In any $*k*$-ary heap every element except for the first one has exactly one parent; for the element 1 the parent is absent (this element is the root of the heap). Denote $*p*(*v*)$ as the number of the parent of the element with the number $*v*$. Let's say that for a non-root element $*v*$ the property of the heap is violated if $*a*_{*v*} < *a*_{*p*(*v*)}$.
Help Andrew cope with the task!
Input
The first line contains a single integer $*n*$ ($2 ≤ *n* ≤ 2·10^{5}$).
The second line contains $*n*$ space-separated integers $*a*_{1}$, $...$, $*a*_{*n*}$ ($- 10^{9} ≤ *a*_{*i*} ≤ 10^{9}$).
Output
in a single line print $*n* - 1$ integers, separate the consecutive numbers with a single space — the number of elements for which the property of the $*k*$-ary heap is violated, for $*k* = 1$, $2$, $...$, $*n* - 1$.
Note
Pictures with the heaps for the first sample are given below; elements for which the property of the heap is violated are marked with red.

In the second sample all elements are equal, so the property holds for all pairs.
样例
5
1 5 4 3 2
3 2 1 0
6
2 2 2 2 2 2
0 0 0 0 0
题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。