Codeforces Round 320 (Div. 1) [Bayan Thanks-Round]
C
Weakness and Poorness
Codeforces
2000
原题
← BD →
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You are given a sequence of n integers $*a*_{1}, *a*_{2}, ..., *a*_{*n*}$.

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Determine a real number $*x*$ such that the weakness of the sequence $*a*_{1} - *x*, *a*_{2} - *x*, ..., *a*_{*n*} - *x*$ is as small as possible.

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The weakness of a sequence is defined as the maximum value of the poorness over all segments (contiguous subsequences) of a sequence.

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The poorness of a segment is defined as the absolute value of sum of the elements of segment.

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Input

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The first line contains one integer $*n*$ ($1 ≤ *n* ≤ 200 000$), the length of a sequence.

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The second line contains $*n*$ integers $*a*_{1}, *a*_{2}, ..., *a*_{*n*}$ ($|*a*_{*i*}| ≤ 10 000$).

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Output

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Output a real number denoting the minimum possible weakness of $*a*_{1} - *x*, *a*_{2} - *x*, ..., *a*_{*n*} - *x*$. Your answer will be considered correct if its relative or absolute error doesn't exceed $10^{ - 6}$.

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Note

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For the first case, the optimal value of $*x*$ is $2$ so the sequence becomes $- 1$, $0$, $1$ and the max poorness occurs at the segment "-1" or segment "1". The poorness value (answer) equals to $1$ in this case.

翻译中…

For the second sample the optimal value of $*x*$ is $2.5$ so the sequence becomes $- 1.5,  - 0.5, 0.5, 1.5$ and the max poorness occurs on segment "-1.5 -0.5" or "0.5 1.5". The poorness value (answer) equals to $2$ in this case.

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样例

Input #1
3
1 2 3
Output #1
1.000000000000000
InputCopy OutputCopy
Input #2
4
1 2 3 4
Output #2
2.000000000000000
InputCopy OutputCopy
Input #3
10
1 10 2 9 3 8 4 7 5 6
Output #3
4.500000000000000
InputCopy OutputCopy
题目信息
题号
578C
时间限制
2 s
内存限制
256 MB
标签
三分

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。