Codeforces Round 342 (Div. 2)
E
Frog Fights
Codeforces
2800
原题
← D→
翻译中…

Ostap Bender recently visited frog farm and was inspired to create his own frog game.

翻译中…

Number of frogs are places on a cyclic gameboard, divided into $*m*$ cells. Cells are numbered from $1$ to $*m*$, but the board is cyclic, so cell number $1$ goes right after the cell number $*m*$ in the direction of movement. $*i*$-th frog during its turn can jump for $*a*_{*i*}$ cells.

翻译中…

Frogs move in turns, game starts with a move by frog $1$. On its turn $*i*$-th frog moves $*a*_{*i*}$ cells forward, knocking out all the frogs on its way. If there is a frog in the last cell of the path of the $*i*$-th frog, that frog is also knocked out. After this the value $*a*_{*i*}$ is decreased by the number of frogs that were knocked out during this turn. If $*a*_{*i*}$ is zero or goes negative, then $*i*$-th frog doesn't make moves anymore.

翻译中…

After frog number $1$ finishes its turn, frog number $2$ starts to move, then frog number $3$ and so on. After the frog number $*n*$ makes its move, frog $1$ starts to move again, then frog $2$ and so on this process goes forever. If some frog was already knocked out from the board, we consider that it skips all its moves.

翻译中…

Help Ostap to identify, what frogs will stay on the board at the end of a game?

翻译中…

Input

翻译中…

First line of the input contains two integers $*n*$ and $*m*$ ($1 ≤ *n* ≤ 100000, 1 ≤ *m* ≤ 10^{9}, *n* ≤ *m*$) — number of frogs and gameboard size, respectively.

翻译中…

Following $*n*$ lines contains frogs descriptions — two integers $*p*_{*i*}$ and $*a*_{*i*}$ ($1 ≤ *p*_{*i*}, *a*_{*i*} ≤ *m*$) — the number of cell occupied by $*i*$-th frog initially and initial jump length. All $*p*_{*i*}$ are guaranteed to be distinct.

翻译中…

Output

翻译中…

In the first line output number of frogs on the final gameboard. In the second line output their numbers in any order.

翻译中…

Note

翻译中…

In the first sample first frog jumps $1$ cell and finishes in cell number $3$. Second frog jumps for $3$ cells and finishes on cell number $3$, knocking out frog number $1$. Current jump length for frog number $2$ is now $2$. Third frog jumps to cell $2$, then second frog jumps to cell $5$. Third frog in turn finishes in cell $5$ and removes frog $2$ from the gameboard. Now, it's the only remaining frog in the game.

翻译中…

In the second sample first frog jumps $2$ cells and knocks out frogs in cells $2$ and $3$. Its value $*a*_{*i*}$ is now $0$. Then fourth frog jumps and knocks out fifth frog and its $*a*_{*i*}$ is now $0$ too. These two frogs will remains on the gameboard forever.

翻译中…

样例

Input #1
3 5
2 1
5 3
4 3
Output #1
1
3
InputCopy OutputCopy
Input #2
5 6
1 2
3 4
2 5
5 1
6 1
Output #2
2
1 4
InputCopy OutputCopy
题目信息
题号
625E
时间限制
2 s
内存限制
256 MB
标签
数据结构
贪心

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。