Codecraft-17 and Codeforces Round 391 (Div. 1 + Div. 2, combined)
C
Felicity is Coming!
Codeforces
1900
原题
← BD →
翻译中…

It's that time of the year, Felicity is around the corner and you can see people celebrating all around the Himalayan region. The Himalayan region has $*n*$ gyms. The $*i*$-th gym has $*g*_{*i*}$ Pokemon in it. There are $*m*$ distinct Pokemon types in the Himalayan region numbered from $1$ to $*m*$. There is a special evolution camp set up in the fest which claims to evolve any Pokemon. The type of a Pokemon could change after evolving, subject to the constraint that if two Pokemon have the same type before evolving, they will have the same type after evolving. Also, if two Pokemon have different types before evolving, they will have different types after evolving. It is also possible that a Pokemon has the same type before and after evolving.

翻译中…

Formally, an evolution plan is a permutation $*f*$ of ${1, 2, ..., *m*}$, such that $*f*(*x*) = *y*$ means that a Pokemon of type $*x*$ evolves into a Pokemon of type $*y*$.

翻译中…

The gym leaders are intrigued by the special evolution camp and all of them plan to evolve their Pokemons. The protocol of the mountain states that in each gym, for every type of Pokemon, the number of Pokemon of that type before evolving any Pokemon should be equal the number of Pokemon of that type after evolving all the Pokemons according to the evolution plan. They now want to find out how many distinct evolution plans exist which satisfy the protocol.

翻译中…

Two evolution plans $*f*_{1}$ and $*f*_{2}$ are distinct, if they have at least one Pokemon type evolving into a different Pokemon type in the two plans, i. e. there exists an $*i*$ such that $*f*_{1}(*i*) ≠ *f*_{2}(*i*)$.

翻译中…

Your task is to find how many distinct evolution plans are possible such that if all Pokemon in all the gyms are evolved, the number of Pokemon of each type in each of the gyms remains the same. As the answer can be large, output it modulo $10^{9} + 7$.

翻译中…

Input

翻译中…

The first line contains two integers $*n*$ and $*m*$ ($1 ≤ *n* ≤ 10^{5}$, $1 ≤ *m* ≤ 10^{6}$) — the number of gyms and the number of Pokemon types.

翻译中…

The next $*n*$ lines contain the description of Pokemons in the gyms. The $*i*$-th of these lines begins with the integer $*g*_{*i*}$ ($1 ≤ *g*_{*i*} ≤ 10^{5}$) — the number of Pokemon in the $*i*$-th gym. After that $*g*_{*i*}$ integers follow, denoting types of the Pokemons in the $*i*$-th gym. Each of these integers is between $1$ and $*m*$.

翻译中…

The total number of Pokemons (the sum of all $*g*_{*i*}$) does not exceed $5·10^{5}$.

翻译中…

Output

翻译中…

Output the number of valid evolution plans modulo $10^{9} + 7$.

翻译中…

Note

翻译中…

In the first case, the only possible evolution plan is:

翻译中…

image

翻译中…

In the second case, any permutation of $(1,  2,  3)$ is valid.

翻译中…

In the third case, there are two possible plans:

翻译中…

image

翻译中…

image

翻译中…

In the fourth case, the only possible evolution plan is:

翻译中…

image

翻译中…

样例

Input #1
2 3
2 1 2
2 2 3
Output #1
1
InputCopy OutputCopy
Input #2
1 3
3 1 2 3
Output #2
6
InputCopy OutputCopy
Input #3
2 4
2 1 2
3 2 3 4
Output #3
2
InputCopy OutputCopy
Input #4
2 2
3 2 2 1
2 1 2
Output #4
1
InputCopy OutputCopy
Input #5
3 7
2 1 2
2 3 4
3 5 6 7
Output #5
24
InputCopy OutputCopy
题目信息
题号
757C
时间限制
2 s
内存限制
256 MB
标签
数据结构
哈希
排序
字符串

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。