Codeforces Round 392 (Div. 2)
D
Ability To Convert
Codeforces
2000
原题
← CE →
翻译中…

Alexander is learning how to convert numbers from the decimal system to any other, however, he doesn't know English letters, so he writes any number only as a decimal number, it means that instead of the letter $*A*$ he will write the number $10$. Thus, by converting the number $475$ from decimal to hexadecimal system, he gets $11311$ ($475 = 1·16^{2} + 13·16^{1} + 11·16^{0}$). Alexander lived calmly until he tried to convert the number back to the decimal number system.

翻译中…

Alexander remembers that he worked with little numbers so he asks to find the minimum decimal number so that by converting it to the system with the base $*n*$ he will get the number $*k*$.

翻译中…

Input

翻译中…

The first line contains the integer $*n*$ ($2 ≤ *n* ≤ 10^{9}$). The second line contains the integer $*k*$ ($0 ≤ *k* < 10^{60}$), it is guaranteed that the number $*k*$ contains no more than $60$ symbols. All digits in the second line are strictly less than $*n*$.

翻译中…

Alexander guarantees that the answer exists and does not exceed $10^{18}$.

翻译中…

The number $*k*$ doesn't contain leading zeros.

翻译中…

Output

翻译中…

Print the number $*x*$ ($0 ≤ *x* ≤ 10^{18}$) — the answer to the problem.

翻译中…

Note

翻译中…

In the first example $12$ could be obtained by converting two numbers to the system with base $13$: $12 = 12·13^{0}$ or $15 = 1·13^{1} + 2·13^{0}$.

翻译中…

样例

Input #1
13
12
Output #1
12
InputCopy OutputCopy
Input #2
16
11311
Output #2
475
InputCopy OutputCopy
Input #3
20
999
Output #3
3789
InputCopy OutputCopy
Input #4
17
2016
Output #4
594
InputCopy OutputCopy
题目信息
题号
758D
时间限制
1 s
内存限制
256 MB
标签
构造
动态规划
贪心
数学
字符串

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