Codeforces Beta Round 67 (Div. 2)
D
Big Maximum Sum
Codeforces
2000
原题
← CE →
翻译中…

Ahmed and Mostafa used to compete together in many programming contests for several years. Their coach Fegla asked them to solve one challenging problem, of course Ahmed was able to solve it but Mostafa couldn't.

翻译中…

This problem is similar to a standard problem but it has a different format and constraints.

翻译中…

In the standard problem you are given an array of integers, and you have to find one or more consecutive elements in this array where their sum is the maximum possible sum.

翻译中…

But in this problem you are given $*n*$ small arrays, and you will create one big array from the concatenation of one or more instances of the small arrays (each small array could occur more than once). The big array will be given as an array of indexes (1-based) of the small arrays, and the concatenation should be done in the same order as in this array. Then you should apply the standard problem mentioned above on the resulting big array.

翻译中…

For example let's suppose that the small arrays are {1, 6, -2}, {3, 3} and {-5, 1}. And the indexes in the big array are {2, 3, 1, 3}. So the actual values in the big array after formatting it as concatenation of the small arrays will be {3, 3, -5, 1, 1, 6, -2, -5, 1}. In this example the maximum sum is 9.

翻译中…

Can you help Mostafa solve this problem?

翻译中…

Input

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The first line contains two integers $*n*$ and $*m*$, $*n*$ is the number of the small arrays ($1 ≤ *n* ≤ 50$), and $*m*$ is the number of indexes in the big array ($1 ≤ *m* ≤ 250000$). Then follow $*n*$ lines, the $*i*$-th line starts with one integer $*l*$ which is the size of the $*i*$-th array ($1 ≤ *l* ≤ 5000$), followed by $*l*$ integers each one will be greater than or equal -1000 and less than or equal 1000. The last line contains $*m*$ integers which are the indexes in the big array, and you should concatenate the small arrays in the same order, and each index will be greater than or equal to 1 and less than or equal to $*n*$.

翻译中…

The small arrays are numbered from 1 to $*n*$ in the same order as given in the input. Some of the given small arrays may not be used in big array.

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Note, that the array is very big. So if you try to build it straightforwardly, you will probably get time or/and memory limit exceeded.

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Output

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Print one line containing the maximum sum in the big array after formatting it as described above. You must choose at least one element for the sum, i. e. it cannot be empty.

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Please, do not use %lld specificator to write 64-bit integers in C++. It is preferred to use cout (also you may use %I64d).

翻译中…

样例

Input #1
3 4
3 1 6 -2
2 3 3
2 -5 1
2 3 1 3
Output #1
9
InputCopy OutputCopy
Input #2
6 1
4 0 8 -3 -10
8 3 -2 -5 10 8 -9 -5 -4
1 0
1 -3
3 -8 5 6
2 9 6
1
Output #2
8
InputCopy OutputCopy
题目信息
题号
75D
时间限制
2 s
内存限制
256 MB
标签
数据结构
动态规划
贪心
模拟
数学
树

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。