Petr wants to make a calendar for current month. For this purpose he draws a table in which columns correspond to weeks (a week is seven consequent days from Monday to Sunday), rows correspond to weekdays, and cells contain dates. For example, a calendar for January 2017 should look like on the picture:

Petr wants to know how many columns his table should have given the month and the weekday of the first date of that month? Assume that the year is non-leap.
Input
The only line contain two integers $*m*$ and $*d*$ ($1 ≤ *m* ≤ 12$, $1 ≤ *d* ≤ 7$) — the number of month (January is the first month, December is the twelfth) and the weekday of the first date of this month ($1$ is Monday, $7$ is Sunday).
Output
Print single integer: the number of columns the table should have.
Note
The first example corresponds to the January 2017 shown on the picture in the statements.
In the second example $1$-st January is Monday, so the whole month fits into $5$ columns.
In the third example $1$-st November is Saturday and $5$ columns is enough.
样例
1 7
6
1 1
5
11 6
5
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