Codeforces Round 397 by Kaspersky Lab and Barcelona Bootcamp (Div. 1 + Div. 2 combined)
E
Tree Folding
Codeforces
2200
原题
← DF →
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Vanya wants to minimize a tree. He can perform the following operation multiple times: choose a vertex $*v*$, and two disjoint (except for $*v*$) paths of equal length $*a*_{0} = *v*$, $*a*_{1}$, ..., $*a*_{*k*}$, and $*b*_{0} = *v*$, $*b*_{1}$, ..., $*b*_{*k*}$. Additionally, vertices $*a*_{1}$, ..., $*a*_{*k*}$, $*b*_{1}$, ..., $*b*_{*k*}$ must not have any neighbours in the tree other than adjacent vertices of corresponding paths. After that, one of the paths may be merged into the other, that is, the vertices $*b*_{1}$, ..., $*b*_{*k*}$ can be effectively erased:

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image

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Help Vanya determine if it possible to make the tree into a path via a sequence of described operations, and if the answer is positive, also determine the shortest length of such path.

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Input

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The first line of input contains the number of vertices $*n*$ ($2 ≤ *n* ≤ 2·10^{5}$).

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Next $*n* - 1$ lines describe edges of the tree. Each of these lines contains two space-separated integers $*u*$ and $*v*$ ($1 ≤ *u*, *v* ≤ *n*$, $*u* ≠ *v*$) — indices of endpoints of the corresponding edge. It is guaranteed that the given graph is a tree.

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Output

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If it is impossible to obtain a path, print -1. Otherwise, print the minimum number of edges in a possible path.

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Note

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In the first sample case, a path of three edges is obtained after merging paths $2 - 1 - 6$ and $2 - 4 - 5$.

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It is impossible to perform any operation in the second sample case. For example, it is impossible to merge paths $1 - 3 - 4$ and $1 - 5 - 6$, since vertex 6 additionally has a neighbour 7 that is not present in the corresponding path.

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样例

Input #1
6
1 2
2 3
2 4
4 5
1 6
Output #1
3
InputCopy OutputCopy
Input #2
7
1 2
1 3
3 4
1 5
5 6
6 7
Output #2
-1
InputCopy OutputCopy
题目信息
标签
DFS 及类似
动态规划
贪心
模拟
树

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。