Codeforces Round 402 (Div. 1)
E
Selling Numbers
Codeforces
3000
原题
← D→
翻译中…

Boris really likes numbers and even owns a small shop selling interesting numbers. He has $*n*$ decimal numbers $*B*_{*i*}$. Cost of the number in his shop is equal to the sum of costs of its digits. You are given the values $*c*_{*d*}$, where $*c*_{*d*}$ is the cost of the digit $*d*$. Of course, Boris is interested in that numbers he owns have the maximum cost possible.

翻译中…

Recently Boris got hold of the magical artifact $*A*$, which can allow him to increase the cost of his collection. Artifact is a string, consisting of digits and '?' symbols. To use the artifact, Boris must replace all '?' with digits to get a decimal number without leading zeros (it is also not allowed to get number 0). After that, the resulting number is added to all numbers $*B*_{*i*}$ in Boris' collection. He uses the artifact exactly once.

翻译中…

What is the maximum cost of the collection Boris can achieve after using the artifact?

翻译中…

Input

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First line contains artifact $*A*$, consisting of digits '0'–'9' and '?' symbols ($1 ≤ |*A*| ≤ 1000$). Next line contains $*n*$ — the amount of numbers in Boris' collection ($1 ≤ *n* ≤ 1000$). Next $*n*$ lines contain integers $*B*_{*i*}$ ($1 ≤ *B*_{*i*} < 10^{1000}$). $*A*$ doesn't start with '0'.

翻译中…

Last line contains ten integers — costs of digits $*c*_{0}, *c*_{1}, ..., *c*_{9}$ ($0 ≤ *c*_{*i*} ≤ 1000$).

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Output

翻译中…

Output one integer — the maximum possible cost of the collection after using the artifact.

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Note

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In the second sample input, the optimal way is to compose the number 453. After adding this number, Boris will have numbers 2656, 5682, 729 and 6696. The total cost of all digits in them is equal to $18 + 15 + 11 + 18 = 62$.

翻译中…

样例

Input #1
42
3
89
1
958
0 0 1 1 2 2 3 3 4 4
Output #1
4
InputCopy OutputCopy
Input #2
?5?
4
2203
5229
276
6243
2 1 6 1 1 2 5 2 2 3
Output #2
62
InputCopy OutputCopy
题目信息
题号
778E
时间限制
2 s
内存限制
512 MB
标签
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