Anton's favourite geometric figures are regular polyhedrons. Note that there are five kinds of regular polyhedrons:
- Tetrahedron. Tetrahedron has
$4$triangular faces. - Cube. Cube has
$6$square faces. - Octahedron. Octahedron has
$8$triangular faces. - Dodecahedron. Dodecahedron has
$12$pentagonal faces. - Icosahedron. Icosahedron has
$20$triangular faces.
All five kinds of polyhedrons are shown on the picture below:

Anton has a collection of $*n*$ polyhedrons. One day he decided to know, how many faces his polyhedrons have in total. Help Anton and find this number!
Input
The first line of the input contains a single integer $*n*$ $(1 ≤ *n* ≤ 200 000)$ — the number of polyhedrons in Anton's collection.
Each of the following $*n*$ lines of the input contains a string $*s*_{*i*}$ — the name of the $*i*$-th polyhedron in Anton's collection. The string can look like this:
- "
Tetrahedron" (without quotes), if the$*i*$-th polyhedron in Anton's collection is a tetrahedron. - "
Cube" (without quotes), if the$*i*$-th polyhedron in Anton's collection is a cube. - "
Octahedron" (without quotes), if the$*i*$-th polyhedron in Anton's collection is an octahedron. - "
Dodecahedron" (without quotes), if the$*i*$-th polyhedron in Anton's collection is a dodecahedron. - "
Icosahedron" (without quotes), if the$*i*$-th polyhedron in Anton's collection is an icosahedron.
Output
Output one number — the total number of faces in all the polyhedrons in Anton's collection.
Note
In the first sample Anton has one icosahedron, one cube, one tetrahedron and one dodecahedron. Icosahedron has $20$ faces, cube has $6$ faces, tetrahedron has $4$ faces and dodecahedron has $12$ faces. In total, they have $20 + 6 + 4 + 12 = 42$ faces.
样例
4
Icosahedron
Cube
Tetrahedron
Dodecahedron
42
3
Dodecahedron
Octahedron
Octahedron
28
题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。