Codeforces Round 455 (Div. 2)
A
Generate Login
Codeforces
1000
原题
←B →
翻译中…

The preferred way to generate user login in Polygon is to concatenate a prefix of the user's first name and a prefix of their last name, in that order. Each prefix must be non-empty, and any of the prefixes can be the full name. Typically there are multiple possible logins for each person.

翻译中…

You are given the first and the last name of a user. Return the alphabetically earliest login they can get (regardless of other potential Polygon users).

翻译中…

As a reminder, a prefix of a string $*s*$ is its substring which occurs at the beginning of $*s*$: "a", "ab", "abc" etc. are prefixes of string "{abcdef}" but "b" and 'bc" are not. A string $*a*$ is alphabetically earlier than a string $*b*$, if $*a*$ is a prefix of $*b*$, or $*a*$ and $*b*$ coincide up to some position, and then $*a*$ has a letter that is alphabetically earlier than the corresponding letter in $*b*$: "a" and "ab" are alphabetically earlier than "ac" but "b" and "ba" are alphabetically later than "ac".

翻译中…

Input

翻译中…

The input consists of a single line containing two space-separated strings: the first and the last names. Each character of each string is a lowercase English letter. The length of each string is between 1 and 10, inclusive.

翻译中…

Output

翻译中…

Output a single string — alphabetically earliest possible login formed from these names. The output should be given in lowercase as well.

翻译中…

样例

Input #1
harry potter
Output #1
hap
InputCopy OutputCopy
Input #2
tom riddle
Output #2
tomr
InputCopy OutputCopy
题目信息
题号
909A
时间限制
2 s
内存限制
256 MB
标签
暴力
贪心
排序

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