AtCoder Beginner Contest 149
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Problem Statement
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Takahashi has come to a party as a special guest. There are $N$ ordinary guests at the party. The $i$-th ordinary guest has a power of $A_i$.
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Takahashi has decided to perform $M$ handshakes to increase the happiness of the party (let the current happiness be $0$). A handshake will be performed as follows:
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- Takahashi chooses one (ordinary) guest
$x$for his left hand and another guest$y$for his right hand ($x$and$y$can be the same). - Then, he shakes the left hand of Guest
$x$and the right hand of Guest$y$simultaneously to increase the happiness by$A_x+A_y$.
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However, Takahashi should not perform the same handshake more than once. Formally, the following condition must hold:
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- Assume that, in the
$k$-th handshake, Takahashi shakes the left hand of Guest$x_k$and the right hand of Guest$y_k$. Then, there is no pair$p, q$$(1 \leq p < q \leq M)$such that$(x_p,y_p)=(x_q,y_q)$.
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What is the maximum possible happiness after $M$ handshakes?
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Constraints
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$1 \leq N \leq 10^5$$1 \leq M \leq N^2$$1 \leq A_i \leq 10^5$- All values in input are integers.
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Input
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Input is given from Standard Input in the following format:
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N M
A_1 A_2 ... A_N
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Output
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Print the maximum possible happiness after $M$ handshakes.
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样例
Input #1
5 3
10 14 19 34 33
Output #1
202
Let us say that Takahashi performs the following handshakes:
- In the first handshake, Takahashi shakes the left hand of Guest $4$ and the right hand of Guest $4$.
- In the second handshake, Takahashi shakes the left hand of Guest $4$ and the right hand of Guest $5$.
- In the third handshake, Takahashi shakes the left hand of Guest $5$ and the right hand of Guest $4$.
Then, we will have the happiness of $(34+34)+(34+33)+(33+34)=202$.
We cannot achieve the happiness of $203$ or greater, so the answer is $202$.
Input #2
9 14
1 3 5 110 24 21 34 5 3
Output #2
1837
Input #3
9 73
67597 52981 5828 66249 75177 64141 40773 79105 16076
Output #3
8128170
题目信息
题面与样例版权归 AtCoder 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。