AtCoder Beginner Contest 149
F
Surrounded Nodes
AtCoder
⌀ 2208
原题
← E→
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Problem Statement

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Given is a tree $T$ with $N$ vertices. The $i$-th edge connects Vertex $A_i$ and $B_i$ ($1 \leq A_i,B_i \leq N$).

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Now, each vertex is painted black with probability $1/2$ and white with probability $1/2$, which is chosen independently from other vertices. Then, let $S$ be the smallest subtree (connected subgraph) of $T$ containing all the vertices painted black. (If no vertex is painted black, $S$ is the empty graph.)

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Let the holeyness of $S$ be the number of white vertices contained in $S$. Find the expected holeyness of $S$.

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Since the answer is a rational number, we ask you to print it $\bmod 10^9+7$, as described in Notes.

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Note

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When you print a rational number, first write it as a fraction $\frac{y}{x}$, where $x, y$ are integers, and $x$ is not divisible by $10^9 + 7$ (under the constraints of the problem, such representation is always possible).

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Then, you need to print the only integer $z$ between $0$ and $10^9 + 6$, inclusive, that satisfies $xz \equiv y \pmod{10^9 + 7}$.

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Constraints

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  • $2 \leq N \leq 2 \times 10^5$
  • $1 \leq A_i,B_i \leq N$
  • The given graph is a tree.
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Input

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Input is given from Standard Input in the following format:

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N
A_1 B_1
:
A_{N-1} B_{N-1}

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Output

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Print the expected holeyness of $S$, $\bmod 10^9+7$.

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样例

Input #1
3
1 2
2 3
Output #1
125000001
If the vertices $1, 2, 3$ are painted black, white, black, respectively, the holeyness of $S$ is $1$. Otherwise, the holeyness is $0$, so the expected holeyness is $1/8$. Since $8 \times 125000001 \equiv 1 \pmod{10^9+7}$, we should print $125000001$.
Input #2
4
1 2
2 3
3 4
Output #2
375000003
The expected holeyness is $3/8$. Since $8 \times 375000003 \equiv 3 \pmod{10^9+7}$, we should print $375000003$.
Input #3
4
1 2
1 3
1 4
Output #3
250000002
The expected holeyness is $1/4$.
Input #4
7
4 7
3 1
2 6
5 2
7 1
2 7
Output #4
570312505
题目信息
题号
abc149_f
时间限制
2 s
内存限制
1024 MB

题面与样例版权归 AtCoder 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。