Codeforces Round 638 (Div. 2)
F
Phoenix and Memory
Codeforces
2600
原题
← E→
翻译中…

Phoenix is trying to take a photo of his $n$ friends with labels $1, 2, \dots, n$ who are lined up in a row in a special order. But before he can take the photo, his friends get distracted by a duck and mess up their order.

翻译中…

Now, Phoenix must restore the order but he doesn't remember completely! He only remembers that the $i$-th friend from the left had a label between $a_i$ and $b_i$ inclusive. Does there exist a unique way to order his friends based of his memory?

翻译中…

Input

翻译中…

The first line contains one integer $n$ ($1 \le n \le 2\cdot10^5$)  — the number of friends.

翻译中…

The $i$-th of the next $n$ lines contain two integers $a_i$ and $b_i$ ($1 \le a_i \le b_i \le n$)  — Phoenix's memory of the $i$-th position from the left.

翻译中…

It is guaranteed that Phoenix's memory is valid so there is at least one valid ordering.

翻译中…

Output

翻译中…

If Phoenix can reorder his friends in a unique order, print YES followed by $n$ integers  — the $i$-th integer should be the label of the $i$-th friend from the left.

翻译中…

Otherwise, print NO. Then, print any two distinct valid orderings on the following two lines. If are multiple solutions, print any.

翻译中…

样例

Input #1
4
4 4
1 3
2 4
3 4
Output #1
YES
4 1 2 3
InputCopy OutputCopy
Input #2
4
1 3
2 4
3 4
2 3
Output #2
NO
1 3 4 2
1 2 4 3
InputCopy OutputCopy
题目信息
题号
1348F
时间限制
2 s
内存限制
256 MB
标签
数据结构
DFS 及类似
图论
贪心

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