Codeforces Round 708 (Div. 2)
C1
k-LCM (easy version)
Codeforces
1200
原题
← BC2 →
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It is the easy version of the problem. The only difference is that in this version $k = 3$.

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You are given a positive integer $n$. Find $k$ positive integers $a_1, a_2, \ldots, a_k$, such that:

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  • $a_1 + a_2 + \ldots + a_k = n$
  • $LCM(a_1, a_2, \ldots, a_k) \le \frac{n}{2}$
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Here $LCM$ is the least common multiple of numbers $a_1, a_2, \ldots, a_k$.

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We can show that for given constraints the answer always exists.

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Input

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The first line contains a single integer $t$ $(1 \le t \le 10^4)$  — the number of test cases.

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The only line of each test case contains two integers $n$, $k$ ($3 \le n \le 10^9$, $k = 3$).

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Output

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For each test case print $k$ positive integers $a_1, a_2, \ldots, a_k$, for which all conditions are satisfied.

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样例

Input #1
3
3 3
8 3
14 3
Output #1
1 1 1
4 2 2
2 6 6
InputCopy OutputCopy
题目信息
题号
1497C1
时间限制
1 s
内存限制
256 MB
标签
构造
数学

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