Codeforces Round 708 (Div. 2)
E2
Square-Free Division (hard version)
Codeforces
2500
原题
← E1→
翻译中…

This is the hard version of the problem. The only difference is that in this version $0 \leq k \leq 20$.

翻译中…

There is an array $a_1, a_2, \ldots, a_n$ of $n$ positive integers. You should divide it into a minimal number of continuous segments, such that in each segment there are no two numbers (on different positions), whose product is a perfect square.

翻译中…

Moreover, it is allowed to do at most $k$ such operations before the division: choose a number in the array and change its value to any positive integer.

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What is the minimum number of continuous segments you should use if you will make changes optimally?

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Input

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The first line contains a single integer $t$ $(1 \le t \le 1000)$  — the number of test cases.

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The first line of each test case contains two integers $n$, $k$ ($1 \le n \le 2 \cdot 10^5$, $0 \leq k \leq 20$).

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The second line of each test case contains $n$ integers $a_1, a_2, \ldots, a_n$ ($1 \le a_i \le 10^7$).

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It's guaranteed that the sum of $n$ over all test cases does not exceed $2 \cdot 10^5$.

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Output

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For each test case print a single integer  — the answer to the problem.

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Note

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In the first test case it is possible to change the array this way: $[\underline{3}, 6, 2, 4, \underline{5}]$ (changed elements are underlined). After that the array does not need to be divided, so the answer is $1$.

翻译中…

In the second test case it is possible to change the array this way: $[6, 2, \underline{3}, 8, 9, \underline{5}, 3, 6, \underline{10}, \underline{11}, 7]$. After that such division is optimal:

翻译中…
  • $[6, 2, 3]$
  • $[8, 9, 5, 3, 6, 10, 11, 7]$
翻译中…

样例

Input #1
3
5 2
18 6 2 4 1
11 4
6 2 2 8 9 1 3 6 3 9 7
1 0
1
Output #1
1
2
1
InputCopy OutputCopy
题目信息
题号
1497E2
时间限制
2 s
内存限制
256 MB
标签
数据结构
动态规划
贪心
数学
数论
双指针

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