Codeforces Round 831 (Div. 1 + Div. 2)
I
Arranging Crystal Balls
Codeforces
3500
原题
← H→
翻译中…

In the world of Compfestnesia, Pak Chanek discovers a secret underground dungeon. Inside it, there is a treasure chest that is surrounded by $n$ statues that are arranged in a circular manner. The statues are numbered from $0$ to $n-1$ with statue $i$ being to the left of statue $i+1$ and statue $n-1$ being to the left of statue $0$.

翻译中…

Pak Chanek observes that each statue is holding a crystal ball with an integer between $0$ and $m-1$ inclusive. Let's say the integer in the crystal ball of statue $i$ is $a_i$.

翻译中…

The dungeon provides instructions that every integer in the crystal balls must be $0$ in order to open the treasure chest. To achieve that, Pak Chanek is given an integer $k$, and he can do zero or more operations. In a single operation, Pak Chanek does the following:

翻译中…
  1. Choose exactly $k$ consecutive statues. In other words, choose the statues $p, (p+1) \bmod n, (p+2) \bmod n, (p+3) \bmod n, \ldots, (p+k-1) \bmod n$ for some chosen index $p$.
  2. Do one of the following:
  • For all chosen statues, change their values of $a_i$ into $(a_i+1) \bmod m$.
    • For all chosen statues, change their values of $a_i$ into $(a_i-1) \bmod m$.
翻译中…

Help Pak Chanek find the minimum possible number of operations to open the treasure chest.

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Input

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The first line contains three integers $n$, $m$, and $k$ ($2 \leq n,m \leq 10^6$, $nm \leq 2 \cdot 10^6$, $1 \leq k \lt n$) — the number of statues, the bound of the integers in the crystal balls, and the number of statues that can be operated in a single operation.

翻译中…

The second line contains $n$ integers $a_0,a_1,\ldots,a_{n-1}$ ($0 \leq a_i \lt m$) — the integers in the crystal balls.

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Output

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If it is possible to perform zero or more operations so that $a_0=a_1=\ldots=a_{n-1}=0$, output the minimum number of operations required. Otherwise, output $-1$.

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Note

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In the first example, Pak Chanek can do the following operations:

翻译中…
  1. Do the $a_i := (a_i-1) \bmod m$ operation $3$ times for statues $1$, $2$, and $3$. Now $a=[8,7,1,2,0]$.
  2. Do the $a_i := (a_i-1) \bmod m$ operation $1$ time for statues $3$, $4$, and $0$. Now $a=[7,7,1,1,8]$.
  3. Do the $a_i := (a_i+1) \bmod m$ operation $2$ times for statues $4$, $0$, and $1$. Now $a=[0,0,1,1,1]$.
  4. Do the $a_i := (a_i-1) \bmod m$ operation $1$ time for statues $2$, $3$, and $4$. Now $a=[0,0,0,0,0]$.
翻译中…

样例

Input #1
5 9 3
8 1 4 5 0
Output #1
7
InputCopy OutputCopy
Input #2
4 4 2
1 0 0 0
Output #2
-1
InputCopy OutputCopy
Input #3
5 5 2
1 0 0 0 0
Output #3
10
InputCopy OutputCopy
题目信息
题号
1740I
时间限制
4 s
内存限制
512 MB
标签
数据结构
分治
动态规划
计算几何
图论
数论

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。