Codeforces Round 254 (Div. 1)
B
DZY Loves FFT
Codeforces
2300
原题
← AC →
翻译中…

DZY loves Fast Fourier Transformation, and he enjoys using it.

翻译中…

Fast Fourier Transformation is an algorithm used to calculate convolution. Specifically, if $*a*$, $*b*$ and $*c*$ are sequences with length $*n*$, which are indexed from $0$ to $*n* - 1$, and

翻译中…

image

翻译中…

We can calculate $*c*$ fast using Fast Fourier Transformation.

翻译中…

DZY made a little change on this formula. Now

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image

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To make things easier, $*a*$ is a permutation of integers from $1$ to $*n*$, and $*b*$ is a sequence only containing $0$ and $1$. Given $*a*$ and $*b*$, DZY needs your help to calculate $*c*$.

翻译中…

Because he is naughty, DZY provides a special way to get $*a*$ and $*b*$. What you need is only three integers $*n*$, $*d*$, $*x*$. After getting them, use the code below to generate $*a*$ and $*b*$.

翻译中…

//x is 64-bit variable;
function getNextX() {
    x = (x * 37 + 10007) % 1000000007;
    return x;
}
function initAB() {
    for(i = 0; i < n; i = i + 1){
        a[i] = i + 1;
    }
    for(i = 0; i < n; i = i + 1){
        swap(a[i], a[getNextX() % (i + 1)]);
    }
    for(i = 0; i < n; i = i + 1){
        if (i < d)
            b[i] = 1;
        else
            b[i] = 0;
    }
    for(i = 0; i < n; i = i + 1){
        swap(b[i], b[getNextX() % (i + 1)]);
    }
}

翻译中…

Operation x % y denotes remainder after division $*x*$ by $*y*$. Function swap(x, y) swaps two values $*x*$ and $*y*$.

翻译中…

Input

翻译中…

The only line of input contains three space-separated integers $*n*, *d*, *x* (1 ≤ *d* ≤ *n* ≤ 100000; 0 ≤ *x* ≤ 1000000006)$. Because DZY is naughty, $*x*$ can't be equal to $27777500$.

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Output

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Output $*n*$ lines, the $*i*$-th line should contain an integer $*c*_{*i* - 1}$.

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Note

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In the first sample, $*a*$ is $[1 3 2]$, $*b*$ is $[1 0 0]$, so $*c*_{0} = *max*(1·1) = 1$, $*c*_{1} = *max*(1·0, 3·1) = 3$, $*c*_{2} = *max*(1·0, 3·0, 2·1) = 2$.

翻译中…

In the second sample, $*a*$ is $[2 1 4 5 3]$, $*b*$ is $[1 1 1 0 1]$.

翻译中…

In the third sample, $*a*$ is $[5 2 1 4 3]$, $*b*$ is $[1 1 1 1 0]$.

翻译中…

样例

Input #1
3 1 1
Output #1
1
3
2
InputCopy OutputCopy
Input #2
5 4 2
Output #2
2
2
4
5
5
InputCopy OutputCopy
Input #3
5 4 3
Output #3
5
5
5
5
4
InputCopy OutputCopy
题目信息
题号
444B
时间限制
1 s
内存限制
256 MB
标签
概率论

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。