8VC Venture Cup 2017 - Final Round
F
Long number
Codeforces
3400
原题
← E→
翻译中…

Consider the following grammar:

翻译中…
  • <expression> ::= <term> | <expression> '+' <term>
  • <term> ::= <number> | <number> '-' <number> | <number> '(' <expression> ')'
  • <number> ::= <pos_digit> | <number> <digit>
  • <digit> ::= '0' | <pos_digit>
  • <pos_digit> ::= '1' | '2' | '3' | '4' | '5' | '6' | '7' | '8' | '9'
翻译中…

This grammar describes a number in decimal system using the following rules:

翻译中…
  • <number> describes itself,
  • <number>-<number> (l-r, $*l* ≤ *r*$) describes integer which is concatenation of all integers from $*l*$ to $*r*$, written without leading zeros. For example, 8-11 describes 891011,
  • <number>(<expression>) describes integer which is concatenation of copies of integer described by <expression>,
  • <expression>+<term> describes integer which is concatenation of integers described by <expression> and <term>.
翻译中…

For example, 2(2-4+1)+2(2(17)) describes the integer 2341234117171717.

翻译中…

You are given an expression in the given grammar. Print the integer described by it modulo $10^{9} + 7$.

翻译中…

Input

翻译中…

The only line contains a non-empty string at most $10^{5}$ characters long which is valid according to the given grammar. In particular, it means that in terms l-r $*l* ≤ *r*$ holds.

翻译中…

Output

翻译中…

Print single integer — the number described by the expression modulo $10^{9} + 7$.

翻译中…

样例

Input #1
8-11
Output #1
891011
InputCopy OutputCopy
Input #2
2(2-4+1)+2(2(17))
Output #2
100783079
InputCopy OutputCopy
Input #3
1234-5678
Output #3
745428774
InputCopy OutputCopy
Input #4
1+2+3+4-5+6+7-9
Output #4
123456789
InputCopy OutputCopy
题目信息
题号
756F
时间限制
2 s
内存限制
512 MB
标签
表达式解析
数学
数论

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。