Codeforces Round 812 (Div. 2)
B
Optimal Reduction
Codeforces
1000
原题
← AC →
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Consider an array $a$ of $n$ positive integers.

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You may perform the following operation:

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  • select two indices $l$ and $r$ ($1 \leq l \leq r \leq n$), then
  • decrease all elements $a_l, a_{l + 1}, \dots, a_r$ by $1$.
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Let's call $f(a)$ the minimum number of operations needed to change array $a$ into an array of $n$ zeros.

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Determine if for all permutations$^\dagger$ $b$ of $a$, $f(a) \leq f(b)$ is true.

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$^\dagger$ An array $b$ is a permutation of an array $a$ if $b$ consists of the elements of $a$ in arbitrary order. For example, $[4,2,3,4]$ is a permutation of $[3,2,4,4]$ while $[1,2,2]$ is not a permutation of $[1,2,3]$.

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Input

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The first line contains a single integer $t$ ($1 \leq t \leq 10^4$) — the number of test cases.

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The first line of each test case contains a single integer $n$ ($1 \leq n \leq 10^5$) — the length of the array $a$.

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The second line contains $n$ integers $a_1, a_2, \dots, a_n$ ($1 \le a_i \le 10^9$) — description of the array $a$.

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It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

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Output

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For each test case, print "YES" (without quotes) if for all permutations $b$ of $a$, $f(a) \leq f(b)$ is true, and "NO" (without quotes) otherwise.

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You can output "YES" and "NO" in any case (for example, strings "yEs", "yes" and "Yes" will be recognized as a positive response).

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Note

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In the first test case, we can change all elements to $0$ in $5$ operations. It can be shown that no permutation of $[2, 3, 5, 4]$ requires less than $5$ operations to change all elements to $0$.

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In the third test case, we need $5$ operations to change all elements to $0$, while $[2, 3, 3, 1]$ only needs $3$ operations.

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样例

Input #1
3
4
2 3 5 4
3
1 2 3
4
3 1 3 2
Output #1
YES
YES
NO
InputCopy OutputCopy
题目信息
题号
1713B
时间限制
1 s
内存限制
256 MB
标签
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