Codeforces Round 812 (Div. 2)
C
Build Permutation
Codeforces
1200
原题
← BD →
翻译中…

A $\mathbf{0}$-indexed array $a$ of size $n$ is called good if for all valid indices $i$ ($0 \le i \le n-1$), $a_i + i$ is a perfect square$^\dagger$.

翻译中…

Given an integer $n$. Find a permutation$^\ddagger$ $p$ of $[0,1,2,\ldots,n-1]$ that is good or determine that no such permutation exists.

翻译中…

$^\dagger$ An integer $x$ is said to be a perfect square if there exists an integer $y$ such that $x = y^2$.

翻译中…

$^\ddagger$ An array $b$ is a permutation of an array $a$ if $b$ consists of the elements of $a$ in arbitrary order. For example, $[4,2,3,4]$ is a permutation of $[3,2,4,4]$ while $[1,2,2]$ is not a permutation of $[1,2,3]$.

翻译中…

Input

翻译中…

The first line contains a single integer $t$ ($1 \le t \le 10^4$) — the number of test cases.

翻译中…

The only line of each test case contains a single integer $n$ ($1 \le n \le 10^5$) — the length of the permutation $p$.

翻译中…

It is guaranteed that the sum of $n$ over all test cases does not exceed $10^5$.

翻译中…

Output

翻译中…

For each test case, output $n$ distinct integers $p_0, p_1, \dots, p_{n-1}$ ($0 \le p_i \le n-1$) — the permutation $p$ — if the answer exists, and $-1$ otherwise.

翻译中…

Note

翻译中…

In the first test case, we have $n=3$. The array $p = [1, 0, 2]$ is good since $1 + 0 = 1^2$, $0 + 1 = 1^2$, and $2 + 2 = 2^2$

翻译中…

In the second test case, we have $n=4$. The array $p = [0, 3, 2, 1]$ is good since $0 + 0 = 0^2$, $3 + 1 = 2^2$, $2+2 = 2^2$, and $1+3 = 2^2$.

翻译中…

样例

Input #1
3
3
4
7
Output #1
1 0 2
0 3 2 1
1 0 2 6 5 4 3
InputCopy OutputCopy
题目信息
题号
1713C
时间限制
1 s
内存限制
256 MB
标签
构造
动态规划
数学

题面与样例版权归 Codeforces 及出题人所有;中文翻译由 AI 生成(CI 管线),如有出入请以原文为准。